The position of a particle s(t)= 3sin1/2t+1. so what is the average velocity of the particle for [0,3pi/2]?

From the question "The position of a particle s(t)= 3sin1/2t+1. So what is the average velocity of the particle for [0,3pi/2]?"

The equation is
s(t) = [3 sin 1] / [2t + 1]

given [0, 3pi/2] then, we can substitute it to the equation
where t = 0
and s(t) = 3pi/2

s(t) = [3 sin 1] / [2t + 1]
s(t) = [3 sin 1] / [2(0) + 1]
s(t) = [3 sin 1] / 3
s(t) = sin 1

So the correct answer is s(t) = sin 1

Did u want to find the value of x?