Someone me ive been trying this problem for 30 minutes

For q(x) = -2x - 2 and r(x) = x^2 + 2

Find the value of q(r(3)).

This is a problem that asks for you to find a function of a function. First things first, you must understand that it is asking you to plug r(3) into q(x) as the value of x. 

Let's start by plugging 3 into r(x). Doing so, you'd get
r(3) = 3^2 + 2

Solve it. 
r(3) = 9 + 2
r(3) = 11

You can see now that q(r(3)) is really q(11). Plug it in.
q(r(3)) = -2(11) - 2

Solve it. 
q(r(3)) = -22 - 2
q(r(3)) = -24

R(3) = 3^2 + 2 = 9 + 2 = 11
q(r(3)) = -2x - 2 = -2(11) - 2 = -22 - 2 = -24

q(r(3)) = -24

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