The probability that emma has heart disease is 0.6. she decides to take a test for the disease that is 80% accurate. what is the probability that emma has heart disease and the test predicts heart disease?

The probability that Emma has heart disease and the test predicts heart disease is:

                                48%

Let A denote the event that Emma has a heart disease.

and B denote the event that the test predicts accurate.

Hence, A∩B denote the event that Emma has heart disease and the test predicts heart disease.

From the given equation we have:

             P(A)=0.6

and P(B)=80%=0.8

As we know that event A and event B are independent.

Hence, we have:

P(A∩B)=P(A)×P(B)

⇒  P(A∩B)=0.6×0.8

⇒  P(A∩B)=0.48=48%

                Hence, the probability is:

                           48%

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9