Aballoon holds 4.2 cubic feet of air. the balloon is blown up larger to hold 5.6 cubic feet of air. what is the percent of change for the volume of air inside the balloon?

We know, percentage change = (final value-Initial value) / Initial value × 100
Here, Initial value = 4.2 Ft³
Final value = 5.6 Ft³

Substitute their values into the expression:
% change = (5.6 - 4.2)/4.2 × 100
% change = 1.4/4.2 × 100
% change = 33.33%

In short, Your Final answer would be 33.33%

Hope this helps!

Initially 4.2 cubic feet,

Blown to 5.6 cubic feet,

% Change =  (5.6 - 4.2) / 4.2      * 100%

                   = 1.4/4.2 *  100%

                   = 1/3 * 100%

                   = 100/3  %

                    = 33    1/3  %

I hope this helps.

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