Using the discriminant, determine the number of real solutions.
-2x^2+x-28=0

Discriminant: b² - 4ac
Equation: y = -2x² + x - 28
a = -2
b = 1
c = -28
1² - (4*-2*28) = 225
-2x² + x - 28 = 225
-2x² + x -(28 -225) = 0   {In order to make it true}
-2x² + x +197 = 0           {Now factorise}
X = 10.177 
     or
X = -9.678

Please double check this. 
My first answer was "No real Roots"...But I did it again and got two figures. You'll have to confirm this with a pair. Sorry. 

Where is the table?

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*