What is the multiple zero and multiplicity of f(x)=x^3-8x^2+16x?

x =0, x =4, x = 4

Step-by-step explanation:

Given: f(x) =

To find the zeros, we need to plug in f(x) = 0, we get

Here x is the common factor, so we can take it out.

Now we can factorize

So

x(x^2 - 8x -16) = 0

x(x-4)(x-4) = 0

x = 0, (x -4) = 0, x-4 = 0

x =0, x = 4, x = 4

Here the two roots are real and equal.

Therefore, the zeros of the given function are x =0 and x = 4 and x = 4

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c