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Mathematics, 01.09.2019 02:50, katdoesart65091
Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.
f(x) = β1/2 times (x β 6)^2 + 3/2
f(x) = 1/2 times (x β 6)^2 + 3/2
f(x) = β1/2 times (x + 3/2)^2 + 6
f(x) = 1/2 times (x + 3/2)^2 + 6
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Answers: 2
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Do you know the correct answer?
Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.
f(x) = β1...
f(x) = β1...
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