Aquadratic function has a line of symmetry at x = –3 and a zero at 4.

q1: what is the distance from the given zero to the line of symmetry?

q2: what is the other zero of the quadratic function?

Part 1)

Part 2) The other zero is

Step-by-step explanation:

we know that

If the line of symmetry is equal to

then

the quadratic function is a vertical parabola and the x-coordinate of the vertex is

Part 1) What is the distance from the given zero to the line of symmetry?

The distance is equal to the absolute value of the difference of from

Part 2) What is the other zero of the quadratic function?

we know that

In a quadratic function the distance from the zero's to the line of symmetry is equal

so

Subtract from

The other zero is

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3