:

when graphed, the circle with equation

x2 + y2 - 14x + 10y + 65 = 0

will lie entirely in quadrant

a) i.
b) ii.
c) iii.
d) iv.

We can rewrite your equation as follows:
(x−7)^2 + (y+5)^2 = 9

namely, you circle has the centre located at (7,-5) and radius equals to 3,

since 3<|-5| and 3<7, your circle lie entirely in the fourth quadrant

Therefore the answer is letter D. IV.

I hope my answer has come to your help. God bless and have a nice day ahead!

Hello there.

When graphed, the circle with equation 

x2 + y2 - 14x + 10y + 65 = 0 

will lie ENTIRELY in Quadrant

D) IV.

The answer to your question is the last one

Dis the correct answer