Which system of equations can be used to solve the following problem?
each child ticket for a ride costs 2$ , while each adult ticket costs 6$ . if the ride collected a total of 148$ , and 38 tickets were sold , how many of each type of ticket were sold? let c be the number of child tickets and a be the number of adult tickets.

a. 2a+6c=38
a+c=148

b. 2c+6a=38
a+c=148

c. 2c+6a=148
a+c=38

d. 6c+2a=148
c+a=38

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?