An auditorium has 15 rows with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth. how many seats are in the auditorium?

 There are total 360 seats in the auditorium.

Step-by-step explanation:  Given that an auditorium had 15 rows  with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth.

We are to find the total number of seats in the auditorium.

Let us write the number of seats in the consecutive rows as a sequence as follows :

10,  12,  14,   .   .   .

If a(n) denote the number of seats in the n-th row, then we see that

So, there is a common difference of 2 in the consecutive terms of the given sequence. That is, the sequence is an arithmetic one.

The total number of seats will be equal to the sum of the first 15 terms of the sequence.

We know that

the sum of first n terms of an ARITHMETIC sequence with first term a and common difference d is given by

In our sequence, a = 10  and  d = 2.

So, the sum of first 15 terms will be

Thus, there are total 360 seats in the auditorium.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743