Abathtub is draining at a constant rate. after 2 minutes, it holds 28 gallons of water. three minutes later, it holds 7 gallons of water. write an equation that represents the number yy of gallons of water in the tub after xx minutes.

(2,28),(5,7)
slope = (7 - 28) / (5 - 2) = - 21/3 = -7...so it is draining at a rate of 7 gallons per minute

y = mx + b
slope(m) = -7
(2,28)...x = 2 and y = 28
now we sub and find b, the y int
28 = -7(2) + b
28 = -14 + b
28 + 14 = b
42 = b
so ur equation is : y = -7x + 42this is basically saying that when full, the bathtub holds 42 gallons and is draining at a rate of 7 gallons per minute

Last one hope this works