The graph of an absolute value function opens down and has a vertex of (-3,0).

the domain of the function is

a) [-3,∞)
b) (-∞,0]
c) (-∞,∞)

the range of the function is

a) [-3,∞)
b) (-∞,0]
c) (-∞,∞)

Suppose that f(0) = −3 and f '(x) ≤ 8 for all values of x. how large can f(4) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 4] . there exists a number c such that

If f(x) = 2x - 6 and g(x) = 3x + 9, find (f - g)(x). a. (f-g)(x) = x + 15 o o b. (f- g)(x) = -x - 15 o c. (f- g)(x) = 5x + 3 o d. (f- g)(x) = -x+3 submit

Find the domain and range of the following function f(x) = 51x - 21+ 4