Figure abcd is transformed to figure a′b′c′d′:

a coordinate grid is labeled from negative 5 to 0 to 5 on both x and y axes at increments of 1. figure abcd has a at ordered pair 1, 1, b at 3, 3, c at 4, 2, d at 4, 1. figure a prime b prime c prime d prime has a prime at ordered pair 1, negative 3, b prime at 3, negative 1, c prime at 4, negative 2, d at 4, negative 3.

which angle in figure a′b′c′d′ is equal to angle cda.?

angle d prime a prime b prime.
angle a prime b prime c prime.
angle b prime c prime d prime.
angle c prime d prime a prime.

The correct option is 4.

Step-by-step explanation:

It is given that figure ABCD is transformed to figure A′B′C′D′.

The vertices of ABCD are A(1,1), B(3,3), C(4,2) and D(4,1).

The vertices of A'B'C'D' are A'(1,-3), B'(3,-1), C'(4,-2) and D'(4,-3).

It is clear that the figure translate 4 units down and the rule of translation is

Translation is a rigid transformation, it means image and preimge are congruent.

Since ABCD is translate 4 units down to make A′B′C′D′, therefore

Congruent part of congruent figures are congruent.

Therefore the correct option is 4.

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.