Apolynomial has two terms. check all of the factoring methods that should be considered.
- common factor
- difference of cubes
- sum of cubes
- difference of squares
- perfect-square trinomial
- factoring by grouping

Suppose that a polynomial has two terms. Consider following methods and polynomials for which these methods can be applied.

A. Common factor. For example, if a polynomial is of form

where  then you can factor it in the following way

B. Difference of cubes.  For example, if a polynomial is of form

then it can be factored as

C. Sum of cubes.  For example, if a polynomial is of form

then it can be factored as

D. Difference of squares.  For example, if a polynomial is of form

then it can be factored as

E and F methods require more then two terms.

A, B, C and D

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

d will be the best answer