Mathematics, 01.10.2019 00:30, pado4776

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =
a^2 + + ( )

Answers: 2

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(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =
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(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) = a^2 + + ( )

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(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =
a^2 + + ( )