Will upvote!
suppose an investment of $8,200 doubles in value every 7 years. how much is the investment worth after 28 years?
a- $65,600
b- $131,200
c- $459,200
d- $114,800

The investment after 28 years is worth $131,200

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

Since the investment doubles in value every 7 years and were are asked the value after 28 years, then we first need to calculate how many times 7 years pass in 28 years. We do this by dividing 28 by 7 like so.....

As we can see the investment will double 4 times. Since it is "Doubling" we can solve this by either multiplying $8,200 by 2 , and then multiplying the answer of that by 2, and so on 4 times. Fortunately, a much easier way would be to raise 2 to the power of 4 and multiply that by $8,200 like so......

Finally we can see that the investment after 28 years is worth $131,200

I hope this answered your question. If you have any more questions feel free to ask away at .

The investment is worth $131,200 after 28 years

Step-by-step explanation:

math

your answer would be 12

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0