George needs to rent a car for one day. he can rent a cadillac from gamma car rental for $30.39 per day plus 55 cents per mile. he can get the same car from delta car rental for $50.31 per day plus 43 cents per mile. what number of miles results in the price for gamma being equal to the price for delta? write your answer as a number only

Call the number of days 'd' and the number of miles 'm'.
(Original, eh ?)

Then the equation for Gamma's price is

                           Price-G = 30.39d + 0.55m

and the equation for Delta's price is

                            Price-D = 50.31d + 0.43m .

We're going to set the prices equal, and find out
what the number of miles is:

                       Price-G = Price-D.

        30.39d + 0.55m  = 50.31d + 0.43m .

Before we go any farther, I'm going to assume that both cases would be
one-day rentals.  My reasons:  ==> the solution for the number of miles
depends on how many days each car was rented for;  ==> even if both
cars are rented for the same number of days, the solution for the number
of miles depends on what that number of days is.

For 1-day rentals, d=1, and

                                        30.39 + 0.55m  =  50.31 + 0.43m .
Beautiful.  Here we go.
Subtract 0.43m
from each side:              30.39 + 0.12m  =  50.31

Subtract 30.39
from each side:                            0.12m  =  19.92

Divide each side by 0.12 :                  m  =  166 .

There it is !  If a car is rented from Gamma for a day, and another car
is rented from Delta for a day, and both cars are driven 166 miles, then
the rental prices for both cars will be the same ... (namely $121.69)

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.