If there is a 30% chance of sun tomorrow and a 20% chance of wind and no sun, what is the probability that it is windy, given that it is not sunny? round your answer to the nearest percent.
a. 44%
b. 29%
c. 22%
d. 57%

B. 29%

Step-by-step explanation:

if there is a 30% chance of sun tomorrow and a 20% chance of wind and no sun.

what is the probability that it is windy, given that it is not sunny.

A: it is not sunny

P(A)=0.7    (since, chance of being sunny=30% then chance of not being sunny=70%)

B:it is windy

A∩B:it is windy and not sunny

P(A∩B)=0.2  (chance=20%)

B/A:it is windy given that it is not sunny

Baye's theorem states that:

P(A∩B)=P(B/A)×P(A)

0.2=P(B/A)×0.7

⇒ P(B/A)= 2/7=0.286

             ≈ 29%

Hence, probability that it is windy, given that it is not sunny is:

 B.  29%

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.