There are ten shirts in your closet, four blue, three green, and three red. you randomly select a different shirt each day. you wear a blue shirt monday, tuesday, and wednesday.

It's a probability problem to find the odds of picking a green or red shirt out of the 10 shirts on Thursday, Friday and Saturday since you have randomly already know you have picked a blue shirt on the other days. Not sure if you have this as a multiple question problem as you didn't list any possible answers (A. 7/20, B. 5/47, C. 2/5, D. 4/125) to the question. A, B, C, D being like 7 chances out of 20, 5 chances out 47, 2 chances out of chances 5 or 4 chances out of 125 (example answers only).

Probability = Number favorable outcomes / total number of outcomes

If you're asking for the probability of drawing said shirt colors on said days:
Assuming there's no replacement (because clothes), the answer would be:
(2/5)•(1/3)•(1/4), which equals 2/60, or 1/30.
The reason:
On Monday, there are 10 shirts, 4 of them blue. So, your chances are 4 out of 10, or 4/10, which reduces to 2/5.
On Tuesday, there are 9 shirts left, 3 of them blue. So, 3/9, or 1/3.
On Wednesday, there are 8 shirts, 2 of them blue. So, 2/8, or 1/4.
You multiply all the fractions together (which is why simplifying helps A TON)
Hope this helps! And sorry about not answering sooner!