Find the equation of the tangent line to the curve y = 2sinx at the point (pi/6,1). the equation of this tangent line can be written in the form y = mx+b. compute m and b

Y = mx + b

1) m = slope of the tangent line = derivative at the point (pi/6, 1)

Function: y = 2sinx

Derivative: y ' = 2cosx

evaluate at x = pi/6=> y ' = 2cos(pi/6) = √3

2) equation using the slope and the point (pi/6, 1)

y - 1 = √3 ( x - pi/6 )

y = √3 x - √3(pi/6) +1 =√3 x + 0.093

y = √3 x + 0.093

m = √3, b = 0.093

Are there any statements?