Transform the quadratic function y=-2x^2-12x-10 into vertex form. find the vertex, x and y intercepts.

Y=-2x^2-12x-10
to find the x value of the vertex find the axis of symmetry which is
-b/2a
=12/2(-2)
=-3
to find the y value of the vertex sub the axis of symmetry back into the original equation. 
y=-2(-3)^2-12(-3)-10
y=8
vertex=(-3,8)
to put it into vertex form use y=a(x-h)^2 +k where h and k are the x and y values of the vertex respectively. 

y=-2(x--3)^2 +8
y=-2(x+3)^2+8

to find the x intercept let y=0

-2x^2-12x-10=0
x^2+6x+5=0 
use quad formula and you will get 
x=-5 and -1

to find the y intercept let x=0

y= -2(0)^2-12(0)-10
y=-10