Davi is mapping out essential and non-essential expenses and is perplexed about where to categorize gift-giving. davi considers splitting gifts into 4 different spending categories (essential—fixed, essential—variable, non-essential, and other—predictable). then, he decides that 4 categories would be too complicated. he thinks that it will be simpler to budget all gifts under one category only and decides on the category “other (predictable)”. in addition, he will open a special savings account only for gift expenses, both for known people and occasions, and for general gifts that he may decide to give in the future.
which statement below is not a reasonable reason for davi’s decision to establish a separate account for gift expenses.
a.
budgeting categories are exact, and gifts can fit into only one of them.
b.
he will be able to give both planned and unplanned gifts that he has budgeted for.
c.
he will still be able to cover other important living expenses.
d.
simplifying will assure that he can follow his budget plans.

The answer is option A.

Which statement below is not a reasonable reason for Davi’s decision to establish a separate account for gift expenses.

A: Budgeting categories are exact, and gifts can fit into only one of them.

Gifts can be purchased if you have money. And for saving money for buying gifts, you need to budget your expenses properly. So, putting gifts under any budget category will do the same thing. You need to just handle your budget properly.

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.  

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.