Select is a function or is not a function to correctly classify each relation.
title
is a function
is not a function
{(3, , , , 7)}
{(1, , , , 4)}
{(2, , , , 8)}
{(0, , , , 5)}

1.) {(3, 7), (3, 6), (5, 4), (4, 7)} ➜ Is not a Function

2.) {(1, 5), (3, 5), (4, 6), (6, 4)} ➜ Is a Function

3.) {(2, 3), (4, 2), (4, 6), (5, 8)} ➜ Is not a Function

4.) {(0, 4), (3, 2), (4, 2), (6, 5)} ➜ Is a Function

Step-by-step explanation:

{(3, 7), (3, 6), (5, 4), (4, 7)} ➜  Is not a Function, since (3, 7), (3, 6) share same x.

{(1, 5), (3, 5), (4, 6), (6, 4)} ➜ Is a Function, since each relation doesn't share the same x.

{(2, 3), (4, 2), (4, 6), (5, 8)} ➜ Is not a Function, since (4, 2), (4, 6) share same x.

{(0, 4), (3, 2), (4, 2), (6, 5)} ➜ Is a Function, since each relation doesn't share the same x.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation: