One zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

x=-2, x=1, x=3

Step-by-step explanation:

Step-by-step explanation:

one zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

the following polynomials have the function  

f(x)=x^3-2x^2-5x+6

note 2 is not a zero of the function

but x=-2

to find the other zeros we say  

f(x)/x+2=x^3-2x^2-5x+6/(x+2)

we have the quadratic equation  

x^2-4x+3

factorizing the above, using factorization method

(x^2-3x-x+3)

(x^2-3x)(-x+3)

x(x-3)-1(x-3)

(x-1)(x-3)

x=1, x=3

the zeros of the function are  

x=-2, x=1,x=3

substituting the values back into the function

we have zero

f(1)=1^3-2(1)^2-5(1)+6

F(1)=0

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: