Write the equation of the line, in standard form, that has a x-intercept of 2 and is parallel to 2x+y=-5

The equation of a line is represented by the affine function y = mx + b, where m represents the slope, b the y-intercept, x and y the coordinates of a point.
First, we need to transform 2x + y = -5 to the y = mx + b form.
First, let's subtract 2x from both sides to have the y on the left side, and all the other variables and numbers on the right side.
2x + y - 2x = -5 - 2x
y = -2x - 5
That's the standard form of the equation. Now we need to find a parallel.
2 parallel lines have the same slope so m = -2. So we get y = -2x + b
By hypothesis, the line have an x-intercept of 2, which means that for y=0, x = 2. Let's insert those coordinates into our equation to find the y-intercept.
y = -2x + b
0 = -2 * 2 + b
0 = -4 + b
Add 4 on both sides to have b on a side and its value on the other
0 + 4 = -4 + 4 + b
4 = b
We found the y-intercept.
So, the equation of the parallel line is y = -2x + 4

I've added a picture of the graphical representation of both lines.

Hope this Helps! :)

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