A community swimming pool has a deep end and a shallow end. The volume of water in the deep end can be represented by (2x2+12x+10) ft3 and the volume of the water in the shallow end can be represented by (4x2−100)ft3. Write the equivalent expression ("simplified") that represents the total volume of the water in the pool in ft3.

The total volume of water in the pool  = ( 6x^3 + 12x^2 - 90x ) ft^3

Step-by-step explanation:

The volume of water in the deep end = (2x^3 + 12x2 + 10x) ft^3

The volume of water in the shallow     =  (4x^3 -100x) ft^3

The total volume of water in the pool  = (2x^3 + 12x2 + 10x)  +  4x^3 -100x)

                                                              = ( 6x^3 + 12x^2 - 90x ) ft^3

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)