Hi i need help please help
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Answers: 2
Mathematics, 21.06.2019 20:40, kaylabethany
How is the equation of this circle written in standard form? x2 + y2 - 6x + 14y = 142 a) (x - 3)2 + (y + 7)2 = 200 b) (x+ 3)2 + (y - 7)2 = 200 (x - 6)2 + (y + 14)2 = 142 d) (x+6)2 + (y- 14)2 = 142
Answers: 1
Mathematics, 21.06.2019 22:00, juhavyen
Determine the domain and range of the given function. the domain is all real numbers all real numbers greater than or equal to β2{x: x = β2, β1, 0, 1, 2}{y: y = β2, β1, 0, 1, 2}. the range is all real numbers all real numbers greater than or equal to β2{x: x = β2, β1, 0, 1, 2}{y: y = β2, β1, 0, 1, 2}.
Answers: 1
Mathematics, 22.06.2019 01:10, hellicuh
Evaluate 8x2 + 9x β 1 2x3 + 3x2 β 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 β 2x = x(2x2 + 3x β 2) = x(2x β 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the formβ 8x2 + 9x β 1 x(2x β 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x β 1)(x + 2), obtaining 8x2 + 9x β 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x β 1).
Answers: 3
Mathematics, 22.06.2019 04:30, Baby010391
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Answers: 1
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