A restaurant/bar conducted random sampling of bar purchases. In a sample of 17 restaurant patrons, they found that, when the background music tempo was slow, the mean purchase amount was $30.47 with a standard deviation of $15.10. In a sample of 14 patrons in the same restaurant, they found that, when the background music tempo was fast, the mean purchase amount was $21.62 with a standard deviation of $14.80. The bar would like to know if they can conclude that background music tempo leads to different average purchase amounts at the bar. What test should be used

Two sample test of means with unknown variance (standard deviation) but assumed equal

Step-by-step explanation:

For the scenario described above, we apply the two sample test means with unknown variance (standard deviation) but assumed equal test because, the there are two differebt or independent groups, each with its owm subjects or observations. The population variance or standard deviation aren't given. However, the variance are assumed to be equal., since the two groups of sample are chosen from the same population. Therefore, for the scenario described above, the most appropriate test would be a Two sample test of means with unknown variance (standard deviation) but assumed to be equal

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.