The mean age at which the population of babies first stand without support is normally distributed with a mean of 13.20 months with a standard deviation of 2.00 months. What is the probability of randomly selecting a sample of 25 children who stood on their own by the average age of 12.2 months or earlier

0.00621

Step-by-step explanation:

We solve the above question using the

Z score formula. This is given as:

z = (x-μ)/σ/√n

where

x is the raw score = 12.20 or earlier

This means x ≤ 12.20

μ is the population mean = 13.20

σ is the population standard deviation = 2

n is the random number of samples = 25

z = 12.2 - 13.2/2/√25

z = -1/2/5

z = -1/0.4

z = -2.5

Probability value from Z-Table:

P(x≤ 12.2) = 0.0062097

Approximately = 0.00621

Therefore, the probability of randomly selecting a sample of 25 children who stood on their own by the average age of 12.2 months or earlier is 0.00621

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

give more details

step-by-step explanation: