I have no idea how to draw these please help

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  1, 2: draw x as the altitude of a right triangle

  3: draw x as double the altitude of the right triangle

Step-by-step explanation:

Consider the right-triangle geometry in the attachment. All of the right triangles are similar, so the ratios of corresponding sides are equal.

  short side / long side = x/r = s/x

You may notice this compares to the required relation in problem 1.

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If you multiply this out, you get ...

  x² = rs   ⇒   x = √(rs)

This compares to the required relation in problem 2.

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So, you append the two line segments to each other so they make segment AB, find their midpoint D (using a perpendicular bisector construction), then draw the (semi-)circle centered at that midpoint. The perpendicular at X will intersect the circle at C, a distance of x from the line rs. (A perpendicular to a line at a point construction is required to create XC.)

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For problem 3, you simply need to double the length √(rs) that you found in the previous constructions. A simple way to do this is to draw a circle, not a semicircle. Then point C' on the lower half of the circle will be 2√(rs) from point C.

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In the attached, we have shown right triangle ABC for discussion purposes above. Segments AC and BC are not needed for your purpose.

Point of clarification: AX = r, BX = s, CX = x.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

correct answer is b. 27/8

step-by-step explanation: