a manufacturer is designing a flashlight for the flashlight to admit a focused beam the bull needs to be on the central axis of the parabolic reflector 33 cm from the vertex write an equation that models the parabola formed when a cross section is taken through the reflector Center access assume that the vertex of the parabola is at the origin of the XY coordinate plane in the parabola can open it any direction​

y= 1/12(x-0)^2+0

this answer works as an upward parabola

Step-by-step explanation:

The formula for a veritcal parabola is y=1/4p(x-h)^2+k(h,k)= coordinates of the vertex of the parabolap= absolute value of the distance from the vertex to the focus/directrixIn this problem, it is given that the vertex is at the origin (0,0) and the focus (the bulb), is 3 centimeters away from the vertex. Now, you know the values of the variables. Fill in the valuesFROM THE FORMULA: 1/4p turns into 1/12 since p is 3.(x-h)^2+k turns into (x-0)^2+0, since h and k where the values of the vertex which was 0,0once all the variables are given values (except x and y) you have made your equation! The answer is y=1/12(x-0)^2+0

MARK BRAINLIEST! this took forever, and I know this is the right answer since I got a perfect grade when I turned mine in.

Where’s the