Solve the third one pls
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Answers: 2
Mathematics, 20.06.2019 18:02, steph1340
Use continuity to evaluate the limit. lim x→16 20 + x 20 + x step 1 consider the intervals for which the numerator and the denominator are continuous. the numerator 20 + x is continuous on the interval the denominator 20 + x is continuous and nonzero on the interval
Answers: 3
Mathematics, 22.06.2019 00:30, ashiteru123
What is the value of x? enter your answer in the box. x =
Answers: 1
Mathematics, 22.06.2019 03:00, IntellTanito
Select quivalent or not equivalent to indicate whether the expression above is equivalent or not equivalent to the values or expressions in the last column.
Answers: 3
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