Given: Quadrilateral ABCD has vertices A(-5,6), B(6,6), C(8,-3), and D(-3,-3). Which of the following ways can prove that quadrilateral ABCD is a parallelogram but is neither
a rhombus nor a rectangle?
A:The diagonals are congruent and perpendicular.
B:The midpoints of the diagonals are the same, the diagonals are not congruent, and
two adjacent sides are not congruent.
C
The four sides are congruent and the diagonals are perpendicular.
D
The slopes of the adjacent sides are negative reciprocals of one another and the
midpoints of the diagonals are the same.

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation:

365

step-by-step explanation: