A basketball game a team made 52 successful shots they were a combination of 1- and 2- point shots the team scored 86 points in all write and solve a system of equations to find the number of each type of shot

15

Step-by-step explanation:

x = one point shots

y = two point shots

1) Setup your equations.

x + y = 52

x + 2y = 89

2) Isolate a variable.

x = 52-y

3) Plug in.

(52-y) + 2y = 89

52 +y =89

y=37

4) Solve for x.

x = 52 -37

x=15

5) Check your answer.

15 + 2(37) = 89

15+74=89

89=89

37+15 = 52

52=52

x = one point shots

y = two point shots

1) Setup your equations.

x + y = 52

x + 2y = 89

2) Isolate a variable.

x = 52-y

3) Plug in.

(52-y) + 2y = 89

52 +y =89

y=37

4) Solve for x.

x = 52 -37

x=15

5) Check your answer.

15 + 2(37) = 89

15+74=89

89=89

37+15 = 52

52=52

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.