Find the required annual interest rate to the nearest tenth of a percent for $5000 to grow to $8500 if the interest is compounded yearly for 3 years.

19.4%

Step-by-step explanation:

Using the compound interest relation :

A = P(1 + r)^t

A = final amount ; r = rate ; t = time ; P = amount invested

8500 = 5000(1 + r)^3

8500 / 5000 = (1 + r)^3

1.7 = (1 + r)^3

Take the cube root of both sides

1.1935 = 1 + r

1.1935 - 1 = r

r = 0.1935

r in % = 0.1935 * 100% = 19.35%

= 19.4%

answer: there are 453.592 grams in a pound.

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.