One antifreeze solution is 26% alcohol and another is 11% alcohol how much of each mixture should be added to make 24 l of a solution tgat is 21% alcohol?

Step-by-step explanation:

One antifreeze solution is 26% alcohol and another is 11% alcohol how much of each mixture should be added to make 24 l of a solution that is 21% alcohol?

Let us represent

First solution =>x

Second solution => y

System of equations

x + y = 24Equation 1

x = 24 - y

26% × x + 11% × y = 21% × 24

= 0.26x + 0.11y = 5.04... Equation 2

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

answer: 48

just remember to use pemdas:

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