Which figure is described below? The point in a plane equidistant from the endpoints of PQ.
1. Ray. 2. Plane. 3. 2 circles. 4. line

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

b.-4 units

all you   do is count how many times you move

y + 11 = (1/4)(x + 16)

step-by-step explanation: