During the day, Lola's dog is tied by rope to a tree in the center of her yard. The scale drawing below shows the area that the dog has to run, in inches. If the actual length of the rope is 11 2/3 feet, what is the scale used in the drawing?

5 /448

Step-by-step explanation:

Radius in drawing = 1 9/16 in

The actual length of rope = 11 2/3 feets

Converting actual length to inches :

1 feet = 12 inches

11 2/3 feets = (11 2/3) * 12 = 140 inches

To obtain the scale used, we divide the Radius in the drawing by the actual length :

1 9/16 ÷ 140

25 /16 ÷ 140

25 /16 * 1 /140

= 25 / 2240

= 5 /448

Hence, scale is 5 /448 times the actual length of drawing

Hence :

The scale used is :

1 feet = 7.4666 inches

idk lol

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.