Ralph has a cylindrical container of parmesan cheese. The diameter of the base of the container is 2.75 inches, and the height is 6 inches. What is the area of a horizontal cross section of the cylinder to the nearest tenth of a square inch?

The solution is given below:

Step-by-step explanation:

The computation of the area of the horizontal cross section of the cyclinder is given below:

In the case when it is a circle

The area of the circle is

= πr^2

= 3.14 × (2.75 ÷ 2)^2

= 11.873 inches^2

In the case when it is a rectangle

The area of the rectangle is

= 6 × 2.75

= 16.5 inches^2

Hence, the above show the calculations

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer