Triangle PRT - status, TS - its higher. Based on the data in the drawing, calculate the length of the altitude drawn from the vertex R to the extreme PT. ​

16 cm

Step-by-step explanation:

We're to find the length of RT.

Apply the leg rule which is given as,

Hypotenuse/leg = leg/part

Hypotenuse = PR = 7.2 + 12.8 = 20 cm

Leg = RT

Part = 12.8 cm

Plug in the values

20/RT = RT/12.8

Cross multiply

RT*RT = 20*12.8

RT² = 256

RT = √256

RT = 16 cm

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3