Michael plots the point with the polar coordinates (-2,-4pi/3) how does he plot this point?

fill in the blanks with the correct answers

Michael first determines which line the angle of rotation places the point on. The line tells Michael that the point must lie in if r is positive or if r is negative.

the radius of 2 tells Michael that the point lies on the second circle of the polar plane. The value of r is negative. Therefore, the point will lie the angle of rotation

answer choices:

quadrant I
quadrant II
quadrant III
quadrant IV
in the same quadrant as
in the opposite quadrant of​

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step-by-step explanation:

the answer is a

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.