A ball is thrown straight up from the top of a building 128 ft tall with an initial velocity of 80 ft per second. The height s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 128 + 80t − 16t^2.
Find the maximum height attained by the ball

hi,

3. 12.15, you are correct.

4.2.01, your first digit is correct,

hope this !

c

step-by-step explanation:

at least i think its

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

it is x=-4

step-by-step explanation: