The maker of a cell phone screen protector would like to estimate the proportion of customers who file a warranty claim. To do so, they select a random sample of 200 customers and determine that the 96% confidence interval for the true proportion of customers who file a warranty claim to be 0.15 to 0.28. Which of these statements is a correct interpretation of the confidence level? Approximately 96% of customers file a warranty claim.

The cell phone screen protector maker can be 96% confident that the interval from 0.15 to 0.28 captures true proportion of customers who file a warranty claim.

If many random samples of size 200 are selected from the population of all customers, approximately 96% of the sample proportions of customers who file a warranty claim will be between 0.15 and 0.28.

If many random samples of size 200 are selected from the population of all customers, about 96% of the intervals constructed from the samples would capture the true proportion of customers who file a warranty claim.

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

answer: hence, function will be

explanation:

since we have given that

cost of a new textbook = $85

according to question, the resale value of a textbook decreases by 25% with each previous owner,

so, our function becomes,

here, y is the total value of the text book after x owners.

hence, function will be

median- 36f

mode - none

mean- 33.7 ~ 34f