5th Grade U. S Studies Weekly- Week 24 Answer Key (Please create one)
Topic: Hardships of War
Ft. Abigail Smith Adams
Ft. Mercy Otis Warren
Ft. Martha Dandridge Custis Washington
Ft. Molly Pitcher
Ft. Phillis Wheatley American Poet
Ft. Sybil Ludington

Q: to collect and hide food our supplies
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Q: Robert Shurtleff's real first name
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Q: general who thanked Sybil Ludington for her bravery
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Q: raising of prices over a period of time
A: (Is this answer, inflation?)

Q: wrote politically plays and poetry
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Q: someone who raises prices on goods that are scarce
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Q: plantation owner
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Q: Congress raised money by selling debt
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Q: took her husband's place in battle
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Two streets intersect at a 30- degree angle. at the intersection, the are four crosswalks formed that are the same length. what type of quadrilateral is formed by the crosswalks?

What are the solutions of the system? y = x^2 + 2x +3y = 4x - 2a. (-1, -6) and (-3, -14)b. (-1, 10) and (3, -6)c. no solutiond. (-1, -6) and (3, 10)

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.