If G(X) = was shifted three units to the left and three units up, what would the new equation be?
A. G(x) = -6
o O
B. G(x) =
+ 6
C. G(x) = +3
(x+3)
D. G(x) =
3
(x - 3)

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.