What are three equivalent expressions for 3x+3(x+y)

3 x + 3 (x + y)

3 (2 x + y)

6 x + 3 y

y = -2 x

y = -2 x (3 (x + y) + 3 x) = 6

(3 (x + y) + 3 x) = 3

(3 x + 3 (x + y)) dx = 3 (x^2 + x y) +

(x^2 + y^2<R^2)(3 (x + y) + 3 x) dx dy = 0

(3 x + 3 (x + y)) dy dx = 0

Step-by-step explanation:

Hope this helps ツ

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

answer: idk wbu

step-by-step explanation: