A deli is offering two specials. The roast beef special gives a profit of $2.30 per sandwich, and the turkey special gives a profit of $3.10 per sandwich. The roast beef special uses two slices of bread and three slices of cheese. The turkey special uses two slices of bread and four slices of cheese. The deli has 120 slices of bread and 160 slices of cheese available for the specials. The deli wants to maximize its profit selling specials. Let x represent the number of roast beef specials and y represent the number of turkey specials. What are the constraints for the problem?

The constraints are as follows;

1) 2·x + 2·y ≤ 120

2) 3·x + 4·y ≤ 160

3) x = 2.30

4) y = 3.10

5) P = 2.3·x + 3.10

Step-by-step explanation:

The question is a word problem, with the analysis as follows;

The profit from the roast beef special per sandwich = $2.30

The profit from the turkey special per sandwich = $3.10

The number of slices of bread in the roast beef special = Two slices

The number of slices of cheese in the roast beef special = Three slices

The number of slices of bread in the turkey special = Two slices

The number of slices of cheese in the turkey special = Four slices

The number of slices of bread the deli has  = 120 slices

The number of slices of cheese the deli has = 160 slices

Let 'x' and represent the number of roast beef special and 'y' represent the number of turkey special the deli makes, then we have the constraints as follows;

For the number of slices of bread used;

2·x + 2·y ≤ 120...(1)

For the number of slices of cheese used;

3·x + 4·y ≤ 160...(2)

x = 2.30

y = 3.10

The profit 'P' is given by the following equation

P = 2.3·x + 3.10.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .