The equation 2x2+2y2−8x−12y+16=0 2 x 2 + 2 y 2 − 8 x − 12 y + 16 = 0 defines a circle. Which of these shows a correct step for determining the center and radius of this circle? Choose all that are correct. (2x2−8x+16)+(2y2−12y+36)=−16+36
(
2
x
2
−
8
x
+
16
)
+
(
2
y
2
−
12
y
+
36
)
=
−
16
+
36

(x−4)2+(y−9)2=5
(
x
−
4
)
2
+
(
y
−
9
)
2
=
5

(x2−4x+4)+(y2−6y+9)=−8+13
(
x
2
−
4
x
+
4
)
+
(
y
2
−
6
y
+
9
)
=
−
8
+
13

x2+y2−4x−6y=−16
x
2
+
y
2
−
4
x
−
6
y
=
−
16

(x−2)2+(y−3)2=5

what do i choose? because all i see is a lot of numbers and words lol

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.