PLEASE HELP What is the equation of the directrix for the following parabola: -8(x-5)=(y+1)^2 a. y=-3
b. x=7
c. y=7
d. x=-3

Suppose that f(0) = −3 and f '(x) ≤ 8 for all values of x. how large can f(4) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 4] . there exists a number c such that

Graph the equationy=x^2 -[tex]y = x^{2} - 2[/tex]

If np3 /nc2 = 6, find the value of n